Tricky NEET Physics Questions & How to Solve Them Faster
NEET’sphysics can be challenged due to its various topics, difficult questions, and time constraints. However, usingagoodapproachwillallow you toaskmoredifficult questions more efficiently. Thestrategiestointroducefrequentlydifficult types of questions and NEETphysics strategies are:
1. Questions Based on Conceptual Understanding These questions often test conceptual clarity.
It may seem difficult at first, butassoonas you understand the underlying principles,youwillbe easier. Example: Two identical balls are dropped from the same height, one heavier than the other. Which one comesto the ground first?
Solution: The answer is that both balls hit the floor at the same time (ignored air resistance). This is because the acceleration isconstant due to the gravity of all objects near thesurfaceoftheEarth. Strategy: Look for keywords for“same”, “same height”, or “gravity”issues. These illustrate the use of basic principles suchas free fall and uniform acceleration.
2. Unit trick questions
These questions may involve using confusing units or needing a unit conversion to resolve the unit correctly.
Example: The energy required to heat a 2 kg body from 10°C to 20°C is 1,000 years.
Solved:
Use the formula.
°
=
°
°
I
°
q =mcît
where:
°
q is thermal energy (1000 j),
°
m is the mass (2 kg),
°
C is the specific heat capacity (unknown).
I
°
îT is the temperature change (20°C -10°C = 10°C). New to order:
°
=
°
°
I
°
=
1000
2
ã
10
=
50
“
j/kg°C.
c =
and
Q
“
=
2-10
1000
“
= 50J/kg°C
Strategy: Always check the units as needed and convert them before joining the formula.
3.. Circular motion and rotation dynamics.
Questions related to circular motion and rotational dynamics can be challenging as they often include several concepts such as central power, torque, and angular speed.
Example: A car travels a circular route with a 100-meter radius at a constant speed of 20 m/s. What is the force of the centrosome that affects a car when the mass is 500 kg?
Solved:
Use the equation for the central force.
°
°
=
°
°
2
°
f
c
“
=
r
MV
2
“
where:
°
=
500
“
kg
m = 500 kg,
°
=
20
“
MS
v = 20 m/s ,,
°
=
100
“
m
r = 100 m. Replace the value:
°
°
=
500
ã
20
2
100
=
500
ã
400
100
=
2000
“
n
f
c
“
=
100
500 U 20
2
“
=
100
500 is 400
“
= 2000n
Strategy: Focus on understanding the relationships between variables of rotational motion. Practice with different kinds of circular movement questions to increase your speed.
4. Work and Energy Theorem
These questions involve work and energy, but can be difficult if you ruin the concept.
Example: Work is done by the force to move objects. If the force acts over the distance to the object, how do you do it if the intensity and shift are at an angle of 30°°?
Solved:
Use a working style.
°
=
°
°
cos
¡ ¡
°
w =fdcosîhhere:
°
f is strength
°
D is a shift
°
îh is the angle (30°) between intensity and shift.
Strategy: Always check whether the intensity and shifts are aligned or aligned by angle. Remove the power vector if necessary.
5. Thermodynamics and heat transfer
Many questions in this field include difficult details such as heat exchange and thermodynamic processes.
Example: The gas expands through the insulation process. What happens to the gas temperature?
Solved:
In the insulated range, the gas operates in the region without heat exchange, leading to a drop in temperature. Strategy: Think about the most important thermodynamic processes and their properties (insulation, isotherms, etc.).
6. Questions with several concepts
These questions may seem challenging as they include several areas of physics. B. Combination of kinesiology, Newton’s law, and work maintenance.
Example: A 5 kg mass block is on a smooth surface. A force of 10 n is applied. What is the acceleration of the block?
Solved:
Use Newton’s second law.
°
=
°
°
f = ma where
°
=
10
“
n
f = 10n and
°
=
5
“
kg
m = 5 kg.
New to order:
°
=
°
°
=
10
5
=
2
“
MS
2
a =
m
f
“
=
5
10
“
= 2 m/s
2
Strategy: Split the question into parts and apply the correct formula to all parts. Find hidden conditions that affect the solution.
7. Optical (refraction and reflection)
Optical problems, particularly those with lenses and mirrors, can be challenging when several concepts involve focal length, magnification, and distance.
Example: The object is placed 30 cm in front of a concave mirror with a focal length of 15 cm. What is the location of the photo?
Solved:
Use the Miller equation.
1
°
=
1
°
+
1
°
f
1
“
=
v
1
“
+
u
1
“
where:
°
=
“
15
“
cm
f = 15 cm (concaver mirror),
°
=
“
30
“
cm
u = 30 cm (object distance),
°
V is the image distance. Replace the value:
1
“
15
=
1
°
+
1
“
30
15
1
“
=
v
1
“
+
30
1
“
Solutions for
°
V:
1
°
=
1
“
15
+
1
30
=
“
2
+
1
30
=
“
1
30
v
1
“
=
15
1
“
+
30
1
“
=
30
2+1
“
=
30
â1
“
therefore,
°
=
“
30
“
cm
V = 30 cm.
Strategy: Practice developing the speed of these calculations using lens and mirror equations.
Tips for faster problem solving:
Practice regularly: The more problems you solve, the faster you will recognize patterns and know which formulas you need to use.
Focus on concepts: Difficult questions often test your understanding of concepts. Enhance the basics to solve your questions faster. Decision of exclusion: Use exclusion in multiple choice questions to quickly reject obviously incorrect answers.
Time Management: Don’t spend too much time on one question. If you stick, mark it and return later.
Mock test: Appears regularly under time to get used to solving problems within the specified time.
Practice this type of question and focus on the core concepts, and you can solve difficult questions in NEET physics faster and more confidently.